x^2+x-1=0,可得:x(x^2+x-1)=x^3+x^2-x=0
所以x^3+x^2=x
所以x^3+2x^2+2006
=x^3+x^2+x^2+2006
=x^2+x+2006
=1+2006
=2007
x+3/2x-4=3/4
5x/2=3/4+4
5x/2=19/4
20x=38
x=19/10
x^2+x-1=0,可得:x(x^2+x-1)=x^3+x^2-x=0
所以x^3+x^2=x
所以x^3+2x^2+2006
=x^3+x^2+x^2+2006
=x^2+x+2006
=1+2006
=2007
x+3/2x-4=3/4
5x/2=3/4+4
5x/2=19/4
20x=38
x=19/10