Question

如图,在△ABC中,AB=AC,AD⊥BC,P为线段AD上一点,PM⊥AB,PN⊥AC,垂足分别为D\M\N.PM与PN

Answer 1

相等,根据三角形定则,PM/DB =AP/AB ,PN/DC=AP/AC ,又因为AB=AC,AD⊥BC,所以DB=DC.

即PM/DB=PN/DC.则 PM=PN.