函数f(x)=asinxcosx+bcos平方x且f(0)=2.f(π/6)=3.求f(X)最小周期、要过程谢谢
2个回答
f(0)=2∴b=2
f(π/6)=3∴a=2√3
∴f(x)=2√3sinxcosx+2cosx^2
化简得:f(x)=√3sin2x+cos2x+1
=2sin(2x+π/3)
T=2π/2=π
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