Question

｛负5分之1a的3次方x的4次方-10分之9a的平方x的3次方｝/｛负5分之3ax的平方｝

Answer 1

[(-a^3x^4/5)-(9a^2x^3/10]/(-3ax^2/5)=[(-2a^3x^4-9a^2x^3)/10]/(-3ax^2/5).

=[2a^2x^2+9ax)/10]*5/3.

=(2a^2x^2+9ax)/6.

=(1/3)a^2x^2+(3/2)ax.