∵ tan a = - 1 / 3
∴ (5 cos a - sin a)/ (sin a + 2 cos a)
=(5 cos a - sin a)÷ cos a / (sin a + 2 cos a)÷ cos a
=(5 - tan a )/ (tan a + 2)
= (5 - (- 1 / 3))/ (- 1 / 3 + 2)
= (5 + 1 / 3)/ (5 / 3)
= (16 / 3)/ (5 / 3)
= 16 / 5
tan a = sin a / cos a
∵ tan a = - 1 / 3
∴ (5 cos a - sin a)/ (sin a + 2 cos a)
=(5 cos a - sin a)÷ cos a / (sin a + 2 cos a)÷ cos a
=(5 - tan a )/ (tan a + 2)
= (5 - (- 1 / 3))/ (- 1 / 3 + 2)
= (5 + 1 / 3)/ (5 / 3)
= (16 / 3)/ (5 / 3)
= 16 / 5
tan a = sin a / cos a