Question

已知5x-4y=0且xy不等于0,求x^2+y^2/x^2-y^2-x+y/x-y的值

Answer 1

5x-4y=0;

x=4y/5;

x^2+y^2/x^2-y^2-x+y/x-y

=（x²+y²-(x+y)²）/(x²-y²)

=(x²+y²-x²-y²-2xy)/(x²-y²)

=-2xy/(x²-y²)

=-2y×(4y/5)/(16y²/25-y²)

=-8y²/5/-9y²/25

=40/9;

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