(1)I=P/U=100W/220V=0.455A
R=U/I=220V/0.455A=484Ω
答:该灯泡正常发光,通过该灯泡的电流是0.455A.该灯泡的灯泡的电阻是484Ω.
(2)W=Pt=100W×10×60s
=60000J
W=Pt=0.1kW×10/60h
=1/60kW·h
答:该灯泡正常工作10分钟,消耗的电能是60000J(1/60kW·h).
(1)I=P/U=100W/220V=0.455A
R=U/I=220V/0.455A=484Ω
答:该灯泡正常发光,通过该灯泡的电流是0.455A.该灯泡的灯泡的电阻是484Ω.
(2)W=Pt=100W×10×60s
=60000J
W=Pt=0.1kW×10/60h
=1/60kW·h
答:该灯泡正常工作10分钟,消耗的电能是60000J(1/60kW·h).