将点A(0,2),点P(1,m)代入直线y1=kx+b可得b=2,k=m-2,
则mx>kx+b>mx-2,
mx>(m-2)x+2>mx-2,
mx-mx>(m-2)x+2-mx>mx-2-mx,
0>-2x+2>-2,
2>x>1