Question

解下列方程组（1）x2/4-y2=1,x-y-2=0:(2)(x-3)2+y2=9,x+2y=0

Answer 1

1.将x-y-2=0变成x=y+2带入x2/4-y2=1中,得3y2-4y=0得y=0或y=4/3得x=2或x=10/3

2带入y=-x/2到(x-3)2+y2=9中,得5x2-24x=0,得x=0；y=0或者x=24/5；y=-12/5