最常见的方法是：将3式子中的x=6-y-2z带入1式和2式,消去x就只剩下一个关于y和z的方程组：12-2y-4z+y+z=2和6-y-2z+2y+z=4.再化简：y-3z=10和y-z=-2,然后两式相减消去y,得4z=12,z=3,带入y-z=-2所以y=1再带入x=6-y-2得：x=-1.所以最后结果：x=-1,y=1,z=3
qwe {2x+y+z=2x+2y+z=4x+y+2z=6
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