ecause EX=(-1*1/3)+0*1/3+1*1/3 =0;EXY=EX^3=(1/3)*(-1)^3+(1/3)1^3=0;
COV(XY)=EXY-EXEY=0;P(X=1,Y=0)=0,P(Y=0)=P(X=0)=1/3;
P(X=1)*P(X=0)=1/3 * 1/3 =1/9,
then P(X=1,Y=0)=0,but P(X=1)*P(X=0)=1/3 * 1/3 =1/9.the conclusion be hold.
ecause EX=(-1*1/3)+0*1/3+1*1/3 =0;EXY=EX^3=(1/3)*(-1)^3+(1/3)1^3=0;
COV(XY)=EXY-EXEY=0;P(X=1,Y=0)=0,P(Y=0)=P(X=0)=1/3;
P(X=1)*P(X=0)=1/3 * 1/3 =1/9,
then P(X=1,Y=0)=0,but P(X=1)*P(X=0)=1/3 * 1/3 =1/9.the conclusion be hold.