x²-y²=1
1/x²+2y/x
设 x=secm,
则 y=tanm
1/x²+2y/x
=cos^m+2tanm*cosm
=cos^m+2sinm
=1-sin^m+2sinm
=2-(sinm-1)^2
所以
-2
若x、y满足条件x²-y²=1,那么1/x²+2y/x的取值范围是
2个回答
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