Question

将4.6g钠投入363.6g水中,求所得溶液中n(Na+):n(H2O)为多少

Answer 1

2Na+2H2O=2NaOH+H2 2Na+46g 36g 2mol4.6g 3.6g 0.2mol 所得溶液中n(Na+):n(H2O)=0.2mol:(363.6-3.6)/18=0.2mol:20mol=1:100