Question

[x的平方-x-6]分之【x的平方-4】除以【x-3]除以【x+1]

Answer 1

[x的平方-x-6]分之【x的平方-4】除以【x-3]除以【x+1]=【x的平方-4】/[x的平方-x-6] 除以【x-3]除以【x+1]=(x+2)(x-2)/(x-3)(x+2) 除以【x-3]除以【x+1]=(x-2)/(x-3) 除以【x-3]除以【x+1]=(x-2)/(x-3) *1/(x-3)除以...