2x^3+3x^2-1
=2X^3+2X^2+X^2-1
=2X^2(X+1)+(X+1)(X-1)
=(X+1)(2X^2+X-1)
=(X+1)(2X-1)(X+1)=0
所以x+1=0 X=-1
2X-1=0 X=1/2
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2x^3+3x^2-1
=2X^3+2X^2+X^2-1
=2X^2(X+1)+(X+1)(X-1)
=(X+1)(2X^2+X-1)
=(X+1)(2X-1)(X+1)=0
所以x+1=0 X=-1
2X-1=0 X=1/2
如果有帮助,请点 评价 并采纳为 满意回答