Question

(1) -(3xy^3)^5-(-3x)^2×(-y)^6×(xy^3)^3= (2)2ab(5ab^2 +3a^2b)

Answer 1

(1) -(3xy^3)^5-(-3x)^2×(-y)^6×(xy^3)^3= -3^5x^5y^15-9x^2y^6x^3y^9=-243x^5y^15-9x^5y^15=-252x^5y^15

(2)2ab(5ab^2 +3a^2b)= 2abx5ab^2 +2abx3a^2b=2x5a^(1+1)b^(1+2)+2x3a^(1+2)b^(1+1)=10a^2b^3+6a^3b^2

(3)(-3x^2 y)×(-x^4)×(-y^3)=-3*(-1)*(-1)x^(2+4)y^(1+3)=-3x^6y^4

(4)[3^2×(a^2)^3]^2=[6×a^2x3]^2=36a^6x2=36a^12