当n->无穷 lim(1+1/2+……+1/2^n

当n->无穷 lim(1+1/2+……+1/2^n)

3个回答

当n趋向于无穷时,为什么lim（1-cos（1/n)=1/2n^2
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级数 Σ[(-1)^n][n/2^n][(x-1)^2n] 当n趋于无穷时lim|Un|^(1/n)=1/2
lim,n趋于无穷,(1+1/2+1/4+...+1/2的N次方)的极限,lim n趋于无穷（1+2+3+.+（n-1
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lim(1/1*2+1/2*3+…+1/n*(n-1)（n趋于无穷）=?
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lim(n->无穷)[(1+3+5+.(2n+1)]/n^2]^(3-2n)