→ × → =15= → × → ×cosA①
AB AC │AB││AC│
→ × → =6= → × → ×cosB②
AB BC │AB││BC│
→ × → =14= → × → ×cosC③
AC BC │AC││BC│
→ →
①-②得:│AB│^2=9,│AB│=3④
→ →
③-②得:│BC│^2=8,│BC│=2√2⑤
将④⑤代入②,cosB=√2/2
所以sinB=√2/2
S=1/2│AB│×│BC│×sinB=3
→ × → =15= → × → ×cosA①
AB AC │AB││AC│
→ × → =6= → × → ×cosB②
AB BC │AB││BC│
→ × → =14= → × → ×cosC③
AC BC │AC││BC│
→ →
①-②得:│AB│^2=9,│AB│=3④
→ →
③-②得:│BC│^2=8,│BC│=2√2⑤
将④⑤代入②,cosB=√2/2
所以sinB=√2/2
S=1/2│AB│×│BC│×sinB=3