是不是a^2-3a+1=0?如果是则
显然a不等于0
所以a-3+1/a=0
a+1/a=3
a^2+2+1/a^2=9
a^2+1/a^2=7
a^3+1/a^3=(a+1/a)(a^2-1+1/a^2)
=3*(7-1)=18
a^3/(a^6+1)
=1/(a^3+1/a^3)
=1/18
是不是a^2-3a+1=0?如果是则
显然a不等于0
所以a-3+1/a=0
a+1/a=3
a^2+2+1/a^2=9
a^2+1/a^2=7
a^3+1/a^3=(a+1/a)(a^2-1+1/a^2)
=3*(7-1)=18
a^3/(a^6+1)
=1/(a^3+1/a^3)
=1/18