弧长C=3450.弦长L=3140,求半径R?
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=2349
R1=2315.87
R2=2316.97
R3=2316.97
R=2316.97
弧长C=3450,高度H=560,求半径R?
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=2656
R1=2550.22
R2=2557.57
R3=2557.61
R4=2557.61
R=2557.61
弦长L=3140,高度H=560,求半径R?
R^2=(R-H)^2+(L/2)^2
R^2=R^2-2*R*H+H^2+L^2/4
2*R*H=H^2+L^2/4
R=H/2+L^2/(8*H)
=560/2+3140^2/(8*560)
=2480.8