x²+2x+1+y²-4y+4=0
(x+1)²+(y-2)²=0
则：x+1=0,y-2=0
∴x=-1,y=2
∴x+y=1
∴(x+y)^2014=1
xy满足x^2+y^2+2x-4y+5=0 （x+y）^2014等于多少
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