6/(x²-9)+(x-3)/(x+3)(x-3)
=6/(x+3)(x-3)+(x-3)/(x+3)(x-3)
=(6+x-3)/(x+3)(x-3)
=(x+3)/(x+3)(x-3)
=1/(x-3)
求解答一题化简 分式6lx∧2-9+1lx+3 l是分号 ∧2是平方
6/(x²-9)+(x-3)/(x+3)(x-3)
=6/(x+3)(x-3)+(x-3)/(x+3)(x-3)
=(6+x-3)/(x+3)(x-3)
=(x+3)/(x+3)(x-3)
=1/(x-3)