结论:在【-π/4,π/8】上是增函数,在【π/8,π/4】上是减函数
-π/4<=x<=π/4时,.-π/4<=2x+π/4<=3π/4
x在单增区间上:-π/4<=2x+π/4<=π/2,解得 -π/4<=x<=π/8
x在单减区间上:π/2<=2x+π/4<=3π/4,解得 π/8<=x<=π/4
3.由(2)得原函数在【-π/4,π/8】上是增函数,在【π/8,π/4】上是减函数
希望能对你有点帮助!
结论:在【-π/4,π/8】上是增函数,在【π/8,π/4】上是减函数
-π/4<=x<=π/4时,.-π/4<=2x+π/4<=3π/4
x在单增区间上:-π/4<=2x+π/4<=π/2,解得 -π/4<=x<=π/8
x在单减区间上:π/2<=2x+π/4<=3π/4,解得 π/8<=x<=π/4
3.由(2)得原函数在【-π/4,π/8】上是增函数,在【π/8,π/4】上是减函数
希望能对你有点帮助!