Question

(1)[(x+y)^2n]^4除以(-x-y)^2n+1(n是正整数)

Answer 1

(1)[(x+y)^2n]^4/(-x-y)^(2n+1)=[(x+y)^2n]^4/[-(x+y)^(2n+1)]=-(x+y)^[2n-(2n+1)]=-(x+y)^(-1)=-1/(x+y)(2)3^1=33^2=93^3=27尾数是73^4=81尾数是13^5=243尾数是3所以尾数是4个一循环2008/4余数是0相当于余4所以3^20...