Question

“例：若ab=1 求代数式a/(a+1)+b/(b+1)的值 ∵ab=1,∴a/（a+1）=ab/（a+1）/b=ab/

Answer 1

∵abc=1.

∴(1)a/(ab+a+1)=a/(ab+a+abc)=1/(bc+b+1).

(2)c/(ac+c+1)=c/(ac+c+abc)=1/(ab+a+1)=abc/(ab+a+abc)=bc/(bc+b+1).

(3)原式=1/(bc+b+1)+b/(bc+b+1)+bc/(bc+b+1)=(bc+b+1)/(bc+b+1)=1.

所以原式=1.