Question

因式分解：（x^5+x^4+x^3+x^2+x+1)^2-x^5

Answer 1

(x^5+x^4+x^3+x^2+x+1)^2-x^5

=(x^6-1)^2/(x-1)^2-x^5

=[x^12-2x^6+1-x^7+2x^6-x^5]/(x-1)^2

=[(x^7-1)(x^5-1)]/(x-1)^2

=(x^6+x^5+x^4+x^3+x^2+x+1)(x^4+x^3+x^2+x+1)