n(SO42-)=a/96
C(SO42-)=1000a/96v mol/L
C(Fe3+)=(2/3)*1000a/96v=1000a/144v mol/L
4/(v/4)=16 溶液被稀释16倍
C(Fe3+)最后 = (1000a/144v)/16=125a/288v mol/L
选D
n(SO42-)=a/96
C(SO42-)=1000a/96v mol/L
C(Fe3+)=(2/3)*1000a/96v=1000a/144v mol/L
4/(v/4)=16 溶液被稀释16倍
C(Fe3+)最后 = (1000a/144v)/16=125a/288v mol/L
选D