Question

设y=arcsinx^2则dy=

Answer 1

y= (arcsinx)^2 or y = arcsin(x^2)

case 1:

y= (arcsinx)^2

dy = 2 [(arcsinx) /√(1-x^2)] dx

case 2:

y= arsin(x^2)

dy = [2x/√(1-x^4)] dx