Question

[6(x-2)²+12(x+2)(x-2)-3(x-1)²(x-2)]÷[3(2-x)]

Answer 1

原式=-[6(x-2)²+12(x+2)(x-2)-3(x-1)²(x-2)]÷[3(x-2)]

=-［2(X-2)+4(X+2)-(X-1)^2］

=-［2X-4+4X+8-X^2+2X-1］

=X^2-8X+5.