2cosBsinA=sinC
2sinAcosB=sin[180-(A+B)]=sin(A+B)
2sinAcosB=sinAcosB+conAsinB
sinAcosB-cosAsinB=0
sin(A-B)=0,-180A=B
--->△ABC是等腰三角形.
2cosBsinA=sinC
2sinAcosB=sin[180-(A+B)]=sin(A+B)
2sinAcosB=sinAcosB+conAsinB
sinAcosB-cosAsinB=0
sin(A-B)=0,-180A=B
--->△ABC是等腰三角形.