解f(x)=sin(2wx)＋√3cos(2wx)
=2[1/2sin(2wx)＋√3/2cos(2wx)]
=2[cos60°sin(2wx)＋sin60°cos(2wx)]
=2sin（2wx+π/3)
f(x)=sin(2wx)＋√3cos(2wx)怎么化成f(x)=sin(2wx＋π/3)
3个回答
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