Question

谁能帮我解出二次根式a+1=a^2

Answer 1

a+1=a^2

则a^2-a=1

a^2-a+1/4=1+1/4

即a^2-2*a*(1/2)+(1/2)^2=5/4

(a-1/2)^2=(√5/2)^2

所以a-1/2=±√5/2

则a=(1±√5)/2