Question

设y=arctan根号(x^2-1)-lnx/根号(x^2-1)求dy

Answer 1

syms x; y=atan((x^2-1)^(1/2))-log(x)/((x^2-1)^(1/2))

y =

atan((x^2 - 1)^(1/2)) - log(x)/(x^2 - 1)^(1/2)

>> diff(y)

ans =

(x*log(x))/(x^2 - 1)^(3/2)

可见答案是对的.

【MATLAB里log(x)表示ln(x),我们习惯的lg(x)用log10(x)表示,以其它数为底的对数用“log(x)”来表示】