1)
DeltaE=E(bonding)-E(antibonding)=E(photon)=hf=hc/lamda(wavelength)
h:Planck constant
c:speed of light
2) Because E(n)=-RhZ^2/n^2
for H atom Z=1,but for He+ Z=2.
so for H,and DeltaE=Rh(1/4-1/36)
but for He+,DeltaE=4Rh(1/4-1/36)
1)
DeltaE=E(bonding)-E(antibonding)=E(photon)=hf=hc/lamda(wavelength)
h:Planck constant
c:speed of light
2) Because E(n)=-RhZ^2/n^2
for H atom Z=1,but for He+ Z=2.
so for H,and DeltaE=Rh(1/4-1/36)
but for He+,DeltaE=4Rh(1/4-1/36)