af(x)+bf(1/x)=cx (1)
令m=1/x,则x=1/m
所以af(1/m)+bf(m)=c/m
所以af(1/x)+bf(x)=c/x (2)
(1)*a-(2)*b
(a²-b²)f(x)=acx-bc/x
f(x)=(acx-bc/x)/(a²-b²)
af(x)+bf(1/x)=cx (1)
令m=1/x,则x=1/m
所以af(1/m)+bf(m)=c/m
所以af(1/x)+bf(x)=c/x (2)
(1)*a-(2)*b
(a²-b²)f(x)=acx-bc/x
f(x)=(acx-bc/x)/(a²-b²)