就相当于用x^4-y^4除以(-x+y)(y^2+x^2)得到的结果,就是所求.
(x^4-y^4)/[(-x+y)(y^2+x^2)]
=[(x^2-y^2)(x^2+y^2)]/[(y-x)(y^2+x^2)]
=(x^2-y^2)/(y-x)
=(x+y)(x-y)/(y-x)
=-(x+y)(y-x)/(y-x)
=-(x+y)
——答案:D
就相当于用x^4-y^4除以(-x+y)(y^2+x^2)得到的结果,就是所求.
(x^4-y^4)/[(-x+y)(y^2+x^2)]
=[(x^2-y^2)(x^2+y^2)]/[(y-x)(y^2+x^2)]
=(x^2-y^2)/(y-x)
=(x+y)(x-y)/(y-x)
=-(x+y)(y-x)/(y-x)
=-(x+y)
——答案:D