Question

设x=1+(2分之1)的100次方,y=1+（2分之1）的-100次方,求y分之x的值

Answer 1

x/y=(1+(1/2)^100)/(1+(1/2)^-100),上下同乘以(1/2)^100得

x/y=(1/2)^100*(1+(1/2)^100)/(1+(1/2)^100)=(1/2)^100.