Question

急求初二数学分式解答x/（x^2-x+1）=7,求x^2/x^4+x^2+1的值.请写出解题步骤,最好详细一点,谢谢啦!

Answer 1

x/（x^2-x+1）=7,求x^2/x^4+x^2+1的值.

∵x/（x^2-x+1）=7

∴x-1+1/x=7

∴x+1/x=8

∴(x+1/x)^2=8^2

∴x^+2+1/x^2=64

∴x^2+1/x^2=62

而原式=(x^2+1/x^2)+1

=62+1

=63

不懂得来问我啊