i2x +3Y -zi+(3X-Y-Z)²
所以
2x +3Y -z=0 (1)
3X-Y-Z =0 (2)
(1)+(2)×3
2x-z+9x-3z=0
11x=4z
z=11x/4
(2)-(1)
x-4y=0
y=x/4
所以原式=(11x/4)/(x+x/4)
=(11x/4)/(5x/4)
=11/5
i2x +3Y -zi+(3X-Y-Z)²
所以
2x +3Y -z=0 (1)
3X-Y-Z =0 (2)
(1)+(2)×3
2x-z+9x-3z=0
11x=4z
z=11x/4
(2)-(1)
x-4y=0
y=x/4
所以原式=(11x/4)/(x+x/4)
=(11x/4)/(5x/4)
=11/5