若x>0,y>0,且根号下x乘(√x+√y)=3√y(√x+√y),求 2x+2√xy+3y 除以x-√xy+y的值
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√x(√x+√y)=3√y(√x+√y)
x+√xy = 3√xy+3y,x-2√xy-3y = 0
∴(√x-3√y)(√x+√y) = 0
∵√x+√y>0
∴√x= 3√y,∴x=9y²
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