换底公式
原式=(lg2/lg3)(lg3/lg4+lg3/lg8)
=(lg2/lg3)(lg3/2lg2+lg3/3lg2)
=(lg2/lg3)(lg3/2lg2)+(lg2/lg3)(lg3/3lg2)
=1/2+1/3
=5/6
log3 2(log 4 3+log8 3)怎么做 2,3在上面
2个回答
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