Question

已知射线OC在平角∠AOB的内部,且∠AOC＞∠BOC,OD平分∠AOC,OE平分∠BOC.

Answer 1

因为OD平分∠AOC,OE平分∠BOC,所以∠COD=1/2∠AOC,∠COE=1/2∠BOC.

又因为∠AOC＞∠BOC,所以∠COD＞∠COE.

∠DOE=∠COD+∠COE=1/2∠AOC+1/2∠BOC=1/2∠AOB