∵AB=AC,AD=AE,BD=CE
∴△ABD≌△AEC(SSS)
∴∠BAD=∠CAE
∵∠BAD=∠BAC+∠CAD
∠CAE=∠CAD+∠DAE
∴∠BAC=∠DAE
∵AB⊥AC即∠BAC=90°
∴∠DAE=90°即AD⊥AE
已知AB⊥AC,AB=AC,AD=AE,BD=CE求证:AD⊥AE
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