Question

已知（x-3)平方+|3y+1|=0,求3x平方y-[2xy平方-2(xy-3/2)+xy]+3xy平方的值.

Answer 1

(x-3)^2+|3y+1|=0

(x-3)^2=0,x=3

|3y+1|=0.y=-1/3

(3x^2)y-[2xy^2-2(xy-3/2)+xy]+3xy^2

=-27/3 - [6/9 - 2(-1 - 3/2) - 1] + 9/9

=-9 - [2/3 + 5 -1] + 1

=-38/3