9,最大值是1,再大就是根号下负数了.
10、(1+1/x)(1+1/y)
=(x+1)/x*(y+1)/y
=(xy+x+y+1)/(xy)
=(xy+2)/xy
=1+2/(xy)
=1+2/[x(1-x)]
欲证明(1+1/x)(1+1/y)>=9,
则要证明1+2/[x(1-x)]>=9
即1/[x(1-x)]>=4
因为x>0、y>0且x+y=1,所以0=4x-4x²
4x²-4x+1>=0
(2x-1)²>=0
上式是成立的,所以,(1+1/x)(1+1/y)>=9成立.
9,最大值是1,再大就是根号下负数了.
10、(1+1/x)(1+1/y)
=(x+1)/x*(y+1)/y
=(xy+x+y+1)/(xy)
=(xy+2)/xy
=1+2/(xy)
=1+2/[x(1-x)]
欲证明(1+1/x)(1+1/y)>=9,
则要证明1+2/[x(1-x)]>=9
即1/[x(1-x)]>=4
因为x>0、y>0且x+y=1,所以0=4x-4x²
4x²-4x+1>=0
(2x-1)²>=0
上式是成立的,所以,(1+1/x)(1+1/y)>=9成立.