Question

ABC为三个随机事件,P(A)=P(B)=P(C)=1/4,P(AB)=P(BC)=1/16,P(AC)=0,求,ABC

Answer 1

∵P(AC)=0

∴P(ABC)=0

P(A'B'C')

=P(AUBUC)'

=1-P(AUBUC)

=1-P(A)-P(B)-P(C)+P(AB)+P(BC)+P(AC)-P(ABC)

=1-1/4-1/4-1/4+1/16+1/16+0-0

=3/8