角A为60°吧,如果是那样的话
∠BDC=180°-(∠DBC+∠DCB)
=180°-2/3(∠ABC+∠ACB)
=180°-2/3(180°-∠A)
=180°-2/3(180°-60°)
=100°
又∵E是⊿BDC的内心 ∴∠CDE=50°
角A为60°吧,如果是那样的话
∠BDC=180°-(∠DBC+∠DCB)
=180°-2/3(∠ABC+∠ACB)
=180°-2/3(180°-∠A)
=180°-2/3(180°-60°)
=100°
又∵E是⊿BDC的内心 ∴∠CDE=50°