388
已知数列{an}满足2a(n-1)-2an=-1(n≥2)且a1=0,数列{bn}满足bn=4的n次方,则数列{b﹜的前
1个回答
相关问题
-
已知数列an bn其中a1=1/2数列an的前n项和Sn=n^2an(n≥1) 数列bn满足b1=2 bn+1=2bn
-
已知数列{an}的前n项和Sn满足Sn=(1/2)*n*an,且a2=1,数列{bn}满足bn+(1/2)b(n-1)=
-
已知数列(an)满足:a1-1,a2-a(a>0),数列(bn)满足bn=ana(n+1)(n∈N)
-
已知数列an与bn满足b(n+1)*an+bn*a(n+1)=(-2)n次方+1,bn=3+(-1)n-1次方/2.
-
设数列{an}的前n项和为Sn,且满足Sn=2-an,n∈N+,数列{bn}满足b1=1,且bn+1=bn+an
-
已知数列{an}满足:a1=1;an+1-an=1,n∈N*,数列{bn}的前n项和为Sn,且Sn+bn=2,n∈N*.
-
已知数列{an}中,a1=35,an=2−1an−1(n≥2,n∈N+),数列{bn}满足:bn=1an−1(n∈N+)
-
3.设数列{an}的前n项和Sn=2an-4(n∈N+),数列{bn}满足:bn+1=an+2bn,且b1=2.求{bn
-
已知数列{an}中a1=[3/5],an=2-[1an−1(n≥2,n∈N*),数列 {bn},满足bn=1a
-
已知数列{an}的前n项和Sn=2^n,数列{bn}满足b1= -1,bn+1=bn+(2n-1)