sin(a+b)cosa-1/2[sin(2a+b)-sinb]化简

1个回答

  • sin(a+b)cosa-1/2[sin(2a+b)-sinb]

    =(sinacosb+cosasinb)cosa-1/2(sin2acosb+cos2asinb-sinb)

    和差公式,全部打开

    =sinacosacosb+cos²asinb-1/2(2sinacosacosb+(2cos²a-1)sinb-sinb)

    二倍角公式打开

    =sinacosacosb+cos²asinb-1/2(2sinacosacosb+2cos²asinb-sinb-sinb)

    依次化简

    =sinacosacosb+cos²asinb-sinacosacosb+cos²asinb-sinb

    =-sin