Question

已知y=ax^5+bx^3+cx-5.当x=-5时y=9.求当x=5时y的值

Answer 1

已知y=ax^5+bx^3+cx-5.当x=-5时y=9.

即a（-5)^5+b(-5)^3+c(-5)-5=9

所以a*5^5+b*5^3+c*5=-14

因此当x=5时,y=a*5^5+b*5^3+c*5-5=-14-5=-19值.